Alright, so, I’m doing this maths challenge at school, since it’s maths week or something, and today (22 of July) is supposed to be Pi Day, because 22/7 is an approximation of Pi… Although, this site begs to differ on that…
Anyways, to celebrate, the head of maths created a challenge for each form group to complete, and I’ve taken on the task of doing the challenge for my form group.
Essentially, the task is to make all the numbers from 0 to 100 using only the digits in your birthyear. As my birthyear is 1992 (making me 17 for those curious), the digits I’m forced to use are 1, 9, 9 and 2. I have to make equations with those four digits to make the numbers, and the four digits have to appear in the equation in the same order as they appear in my birthyear (annoyingly).
You can use any mathematical operation (including square roots, but if you go to put something to the power of something else, it has to be one of the four birthyear digits) to create the numbers.
So far, I’ve gotten all but 67 and 69. Any suggestions?
Also, if you spot any equations that I’ve botched, please comment and tell me.
AMMENDMENT: If I can use Permutations (I’m going to find out if I can), then 67 = 1 – √(9)! + 9nPr2, and 69 = -(1*√(9)) + 9nPr2, as 9nPr2 = 72.
AMMENDMENT 2: I can use Permutations, but I figured out another way to do 67 while lying in bed this morning, after hitting snooze on my alarm clock.
zzZzzZzzZz- 67!
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0 = 1 + 9/9 – 2
1 = -1 + 9 -9 +2
2 = 1 – 9/9 + 2
3 = 1 + 9 – 9 + 2
4 = 1 + 9/9 + 2
5 = 1 + 9 – √(9) – 2
6 = 1^9 + √(9) + 2
7 = 1 + 9 – √(9) + 2
8 = -1 – 9 + 9*2
9 = (1*9 + 9)/2
10 = 1 – 9 + 9*2
11 = 1^9 * 9 +2
12 = 1^9 + 9 + 2
13 = 1 + √(9)! + √(9)*2
14 = 19 – √(9) – 2
15 = -1 + 9 + 9 – 2
16 = 1 + 9 + √(9)*2
17 = 1 + 9 + 9 – 2
18 = 1*√(9)*√(9)*2
19 = 1^9 + 9*2
20 = (1^9 + 9)*2
21 = 1 + 9 + 9 + 2
22 = (-1 + 9 + √(9))*2
23 = -1 + (9 + √(9))*2
24 = -1 + (9*√(9)) – 2
25 = 1*9*√(9) – 2
26 = -1 + 9 + 9*2
27 = 1*9 + 9*2
28 = 1 + 9 + 9*2
29 = 1*9*√(9) + 2
30 = 19 + 9 + 2
31 = 1 + (√(9)!)*(√(9) + 2)
32 = (1 + 9)*√(9) + 2
33 = (1*√(9))*(9 + 2)
34 = 1*√(9)!*√(9)! – 2
35 = (-1 + √(9)!)*(9 – 2)
36 = (-1 + 9)*(9/2)
37 = 19 + 9*2
38 = 1*√(9)!*√(9)! + 2
39 = (-1 + √(9)!)! – 9^2
40 = (1 + 9)*(√(9)! – 2)
41 = -1 + (√(9)!)*(9 – 2)
42 = (1 + √(9))! + (9*2)
43 = 1 + (√(9)!)*(9 – 2)
44 = (1 + √(9))*(9 + 2)
45 = (1 + 9)*(9/2)
46 = 1 + 9*(√(9) + 2)
47 = -1 + (√(9)!)*(√(9)! + 2)
48 = (1 + √(9)! – √(9)!)*2
49 = (-1 + 99)/2
50 = (1 + 99)/2
51 = -1 + 9*√(9)! – 2
52 = (1*9)*(√(9)!) – 2
53 = 1 + 9*(√(9)!) – 2
54 = 1 * 9 * √(9) * 2
55 = -1 + 9*√(9)! + 2
56 = (19 + 9)*2
57 = 1 + 9*(√(9)!) + 2
58 = (1 + 9)(√(9)!) – 2
59 = 19*√(9) + 2
60 = (1 + 9)*(√(9)*2)
61 = (1 + √(9)!)*9 – 2
62 = (1 + 9)(√(9)!) + 2
63 = (1*9)*(9 – 2)
64 = (-1 + 9)*(√(9)! + 2)
65 = (1 + √(9)!)*9 + 2
66 = (1*√(9)!)*(9 + 2)
67 = 1 + (√(9)!)(9 + 2)
68 = -(1 + √(9))! + 92
69 = -1*√(9) + 9nPr2
70 = (1 + 9)*(9 – 2)
71 = -1 + 9*(√(9)!) + 2
72 = (-1 + 9)*(√(9))^2
73 = 1 + 9(√(9)! + 2)
74 = (-1 + 9)*9 + 2
75 = -(1*(√(9)!))+9^2
76 = 19*(√(9)! – 2)
77 = (1 + √(9)!)*(9 – 2)
78 = -1 + 9*9 – 2
79 = 1*9*9 – 2
80 = (1 + 9)(√(9)! + 2)
81 = (1^9)*(9^2)
82 = -1 – 9 + 92
83 = -(1*9) + 92
84 = 1 – 9 + 92
85 = -(1 + √(9)!) + 92
86 = -(1*√(9)!) + 92
87 = -(-1 + √(9)!) + 92
88 = (-1 + 9)*(9 + 2)
89 = -1 + 9 + 9^2
90 = (1 + 9)*(√(9))^2
91 = 1 + 9 + 9^2
92 = (1 + 9)*9 + 2
93 = 1^9 + 92
94 = -1 + √(9) + 92
95 = 19*(√(9)+2)
96 = -1 + 99 – 2
97 = 1*99 – 2
98 = 1 + 99 – 2
99 = (1*9)*(9 + 2)
100 = (1^9 + 9)^2
soooooooo much effort :S
Then we spent all physics finding these answers and recess and I’m assuming he did it all in software…. lul!
and i though he wouldn’t do it this morning.
Oh! You botched 69, (its not answered…) SHAME!
Impressive maths skill
Woah, I’m not that advanced in maths to do all this random Pr stuff Lol. I understand the rest though.
What a complete waste of time.. That has done no good except improve your mental math or programming skills (it probably would have been easier to make an app that can try all possibilities.)
My maths teacher made us do something similar to this back in high school. Good times.
This is way to ez!